ABC Wastewater Collection Level 2 Practice Exam 2025 – All-in-One Resource to Master Your Certification!

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What is the water horsepower requirement for a centrifugal pump achieving a flow rate of 550 gpm against a total dynamic head of 75 ft and a specific gravity of 1.2?

10.8 whp

12.5 whp

To determine the water horsepower (whp) requirement for a centrifugal pump, the formula used is as follows:

\[ \text{whp} = \frac{Q \times H \times SG}{3960} \]

Where:

- \( Q \) is the flow rate in gallons per minute (gpm),

- \( H \) is the total dynamic head in feet,

- \( SG \) is the specific gravity of the fluid.

Given the values:

- Flow rate \( Q = 550 \) gpm,

- Total dynamic head \( H = 75 \) ft,

- Specific gravity \( SG = 1.2 \).

Now substituting these values into the formula:

\[ \text{whp} = \frac{550 \times 75 \times 1.2}{3960} \]

Calculating this step by step:

1. Multiply the flow rate and head:

\( 550 \times 75 = 41250 \),

2. Multiply by the specific gravity:

\( 41250 \times 1.2 = 49500 \),

3. Finally, divide by 3960:

\( \frac{49500}{3960} \approx 12

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15.3 whp

6.4 whp

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